4 ms·
In some sense, the existing wire is already that. But your question raises a great point: how was it established that Manhattan is actually on the _inside_ of t
by PessimalDecimal 1y ago
In some sense, the existing wire is already that. But your question raises a great point: how was it established that Manhattan is actually on the _inside_ of this wire and not on the outside? Not very non-Euclidean to assume one way or the other.