3 ms·
It depends if you consider "speedup" to mean dividing the runtime or applying a function to the runtime. I.e. you are saying and f(n) speedup means T(n)/f(n),
by wasabi991011 1y ago
It depends if you consider "speedup" to mean dividing the runtime or applying a function to the runtime.
I.e. you are saying and f(n) speedup means T(n)/f(n), but others would say it means f(T(n)) or some variation of that.
- morepedantic 1y agoThe man, or llm, used the mathematically imprecise definition of exponential in a sentence with a big-O notation. I don't think he's going to be writing entire arguments formally.