2 ms·
I interpreted that as n->log(n) since log and exp are inverses. Also because I've often heard tha the quantum Fourier transform is an exponential speedup over
by wasabi991011 1y ago
I interpreted that as n->log(n) since log and exp are inverses.
Also because I've often heard tha the quantum Fourier transform is an exponential speedup over the discrete Fourier transform, and there the scaling goes n^2->nlogn.