4 ms·
That is something else entirely.
by bobmcnamara 1y ago
That is something else entirely.
- timewizard 1y agoThen if you know what the OP meant why did you ask?
- Grimblewald 1y agobecause they made a nonsensical claim that doesn't align with my (and likely their) understanding of what the FT is and does. The FT is _NOT_ just a convolution, but under certain conditions a specific operation on FT terms is equivalent to a convolution.
- bobmcnamara 1y agoI didn't know what they meant. There are so many FFT tricks. I was hoping this was another.