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It's a reference to a unit type. unit is pretty useless (like void in Java). It's sort of a silly thing you wouldn't do in real production code, just whoever wr

by Macha 1y ago

It's a reference to a unit type. unit is pretty useless (like void in Java). It's sort of a silly thing you wouldn't do in real production code, just whoever wrote this example picked a type that is short to type, would be understood by a Rust programmer, and doesn't require any external context.

38 1y ago
"u8" would have done the job fine and actually been readable
- Macha 1y ago
  It would need to be &u8, as without a reference, you won't have any captured lifetimes, and therefore it wouldn't serve as an example for the capturing lifetime feature. &u8 is also a mostly pointless type in reality.