3 ms·
Yeah, in that case I guess it is usually memory-bound? When it is memory-bound you don't really care that much about scheduling etc.
by pca006132 1y ago
Yeah, in that case I guess it is usually memory-bound? When it is memory-bound you don't really care that much about scheduling etc.
- saagarjha 1y agoMatrix multiplies are typically compute bound, but you don't get much option to improve the actual algorithm because Nvidia gives you an accelerator for one and anything else would be slower.