3 ms·
>because the algorithms they're talking about depend on the Lipschitz property, not the differentiability. That is why the definition should not contain the di
by constantcrying 1y ago
>because the algorithms they're talking about depend on the Lipschitz property, not the differentiability.
That is why the definition should not contain the differentiability condition. It is violated by the examples and irrelevant.
My point is that the Lipschitz property, as defined e.g. in the Wikipedia article, is the important part. Also assuming differentiability is unhelpful, because it misses the point and is even violated by the rest of the article.
- kragen 1y agoYou seem to have sedulously avoided answering my question.