3 ms·
What does zero-overhead mean here?
by Too 1y ago
What does zero-overhead mean here?
- rcarmo 1y agoRaw protocol, really. No marshaling, no conversions, none of the overhead from type management you get with modern Python, none of the turtles-all-the-way-down dependencies of NodeJS equivalents. I like it, although I would probably port it back to “lightweight” Python in about half the size :)