3 ms·
No, because propagation delay is the same.
by formerly_proven 1y ago
No, because propagation delay is the same.
- Jabrov 1y agoYep! That's a key thing to keep in mind here. As chips get bigger (especially at higher frequencies), propagation delay becomes an important blocker
- adgjlsfhk1 1y agoit would be really interesting to see how this played out. the entire way you build circuits changes. e.g. current adder designs use extra transistors to save carry propagation latency, but for optical, that might make the latency worse...
- colechristensen 1y agoPropagation delay is not the same, electrical signals travel much slower in semiconductors than light in a vacuum. If you could make an entirely optical chip, size would matter a whole lot less because light will travel much faster through whatever that material will be.
- nyeah 1y agoPropagation delay for light in a semiconductor tends to be roughly equal to propagation delay for electrical signals in a semiconductor. It's not exactly equal because the dielectric constant is a function of frequency. This is assuming you use a waveguide and travelling waves to send the electrical signals. If you charge up the whole line then, sure, that's slower.
- tbrownaw 1y agoMake wave pipelining cool again?