C itself is fast; it's calls to C from Ruby that are slow. [1] Crossing the Ruby -> C boundary means that a JIT compiler cannot optimize the code as much; beca

C itself is fast; it's calls to C from Ruby that are slow. [1] Crossing the Ruby -> C boundary means that a JIT compiler cannot optimize the code as much; because it cannot alter or inline the C code methods. Counterintuitively this means that rewriting (certain?) built-in methods in Ruby leads to performance gains when using YJIT. [2] [1]: https://railsatscale.com/2023-08-29-ruby-outperforms-c/ https://railsatscale.com/2023-08-29-ruby-outperforms-c/ [2]: https://jpcamara.com/2024/12/01/speeding-up-ruby.html https://jpcamara.com/2024/12/01/speeding-up-ruby.html