I'm guessing because their understanding is still wrong: 3> log10 5 + 5 + log10 5 + 5 ;; i.e. (log10 5 + 5) + (log10 5 + 5) 2.0 In Rebol this would be

I'm guessing because their understanding is still wrong: 3> log10 5 + 5 + log10 5 + 5 ;; i.e. (log10 5 + 5) + (log10 5 + 5) 2.0 In Rebol this would be equivalent to (log10 (5 + (5 + (log10 (5 + 5)))))