3 ms·
900MM-users div 180KK-servers = 5000 users/server Considering only a fraction of that is concurrent users at any given time (maybe 10%), it still seem a bit ex
by powertower 14y ago
900MM-users div 180KK-servers = 5000 users/server
Considering only a fraction of that is concurrent users at any given time (maybe 10%), it still seem a bit excessive, but they're not running a web server, they're pushing data around so it's a bit different.
They also have to handle peak times and have redundancy.