3 ms·
> In the quote you pulled, n is time. It's definitely not. If their usage of O(n) has n as time, then they wouldn't say an O(n^2) startup has accelerated growt
by wavemode 1y ago
> In the quote you pulled, n is time.
It's definitely not. If their usage of O(n) has n as time, then they wouldn't say an O(n^2) startup has accelerated growth of the key metric. You'd be squaring the time, which means slowing down growth of the key metric.
When they say O(n^2) startup they clearly mean a startup which achieves n^2 results in n time. Which is the opposite of how the notation would typically be used.
> No, you don't know how the notation is used.
No, you're confidently wrong.
- thaumasiotes 1y ago>> In the quote you pulled, n is time. > It's definitely not. > When they say O(n^2) startup they clearly mean a startup which achieves n^2 results in n time. How did you manage to write this down without noticing what you were saying?