3 ms·
Take a closer look at a picture of Kruskal coordinates, e.g.: https://upload.wikimedia.org/wikipedia/commons/1/1c/Kruskal_diagram_of_Schwarzschild_chart.svg htt
by jiggawatts 1y ago
Take a closer look at a picture of Kruskal coordinates, e.g.: https://upload.wikimedia.org/wikipedia/commons/1/1c/Kruskal_diagram_of_Schwarzschild_chart.svg https://upload.wikimedia.org/wikipedia/commons/1/1c/Kruskal_...
Those closer-and-closer line spacings are hiding a mathematical infinity, which isn't physical for finite-lifetime black holes.
Conversely, look at: https://en.wikipedia.org/wiki/Eddington%E2%80%93Finkelstein_coordinates#Schwarzschild_metric https://en.wikipedia.org/wiki/Eddington%E2%80%93Finkelstein_...
The ordinary Schwarzschild metric diagram in that article makes it crystal clear that in-falling observers asymptotically approach the horizon, but never cross it.
Read the next section as well, which uses the "Tortoise coordinate"... which again uses the mathematical infinity to allow the horizon to be crossed.
I really don't understand why people keep arguing about this!
If you find yourself writing an infinity symbol, you've failed at physics. Stop, go back, rethink your mathematics.
- ubercow13 1y agoThe article you linked says precisely that Kruskal–Szekeres coordinates are not singular at the event horizon. The event horizon is completely regular: https://en.wikipedia.org/wiki/Gravitational_singularity#Curvature https://en.wikipedia.org/wiki/Gravitational_singularity#Curv... You can choose stupid coordinates that introduce a singularity wherever you like, in GM or in classical mechanics just the same. The coordinates have no meaning.