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Sure, remove unsafePerformIO and you have a sandboxable language. THe point isn't that Haskell doesn't have an escape hatch. The point is that -as usual :)- J
by cryptonector 1y ago
Sure, remove unsafePerformIO and you have a sandboxable language. THe point isn't that Haskell doesn't have an escape hatch. The point is that -as usual :)- Java is borrowing Haskell's best ideas [decades later :)]. It's a good thing.
- dllthomas 1y agoNit, but you also have to remove unsafeCoerce, some pointer stuff, and possibly a few other things.