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It is written The researchers calculated that the process of Hawking radiation theoretically also applies to other objects with a gravitational field but: d
by blueflow 1y ago
It is written
The researchers calculated that the process of Hawking radiation theoretically also applies to other objects with a gravitational field
but: doesn't this only apply if these objects if they have some sort of decay process going on? There are nuclides that have never been observed decaying. I would expect a white dwarf to burn out, go through radioactive decay (unstable nuclides -> stable ones) and end up as inert rock (stable nuclides) at background temperature.
- dist-epoch 1y agoRegular "stable nuclides" stuff which falls into a black hole gets spit out as Hawking radiation, so no, this is a gravitational process, radioactive decay is a standard model one.
- jfengel 1y agoHawking radiation doesn't require decay. Pairs of particles appear spontaneously. One falls into the gravitational field, losing energy. The net energy loss comes from the gravitational field of the object, and its mass decreases. We don't have details on just what that means at a Standard Model level, but the net loss of energy means something is going to disappear even without any kind of previously understood decay.
- dist-epoch 1y ago> Pairs of particles appear spontaneously. One falls into the gravitational field, losing energy. That's not really true. Even Hawking admitted that's it's a simplification he did for his popular science book of what really is going on. https://www.youtube.com/watch?v=UxVssUb0MsA https://www.youtube.com/watch?v=UxVssUb0MsA
- leptons 1y agoHawking never knew "what really is going on". He wrote some nice hypotheses, but he never knew for sure, and was not ever close to knowing.
- computerthings 1y ago[dead]
- MattPalmer1086 1y agoBut he did know the simplification was wrong.
- mr_toad 1y agoNo, all objects with non-zero temperature radiate heat. Stars, white dwarfs, black holes, even the universe itself.
- blueflow 1y agoI said inert rock at background temperature so radiated and absorbed heat should already be accounted for, right?
- pixl97 1y ago>here are nuclides that have never been observed decaying Aren't we pretty sure due to things like quantum tunneling that the probability of any quantum particle existing trends to zero given a long enough time?
- cvoss 1y agoThe whole point of Hawking radiation is that a thing which famously shouldn't have a decay process (a black hole) in fact does have a decay process due to the interaction of gravity and quantum mechanics.