3 ms·
That's not true. If there are measurable performance differences.
by kridsdale3 1y ago
That's not true. If there are measurable performance differences.
- kadushka 1y agoIf you get any accuracy degradation with full 8 bits of precision you're doing it wrong.
- omneity 1y agoOr your model wasn't trained so well (weights are too spiky)
- danielmarkbruce 1y ago"strict" means something. People, including yourself, only care if there is a practical difference in performance. "this is lossless and that isn't lossless" is a completely useless statement in this realm. In many domains lossy compression is either not tolerated, not legal or not practical.