4 ms·

Yes the dirac comb for example. Actually there are infinitely many. https://en.wikipedia.org/wiki/Dirac_comb https://en.wikipedia.org/wiki/Dirac_comb and for

• abetusk 1y ago
  A question I hadn't even thought to ask, thanks. So, basically, the eigenfunctions of the Fourier transform are Hermite polynomials times a Gaussian [0] [1]. [0] https://math.stackexchange.com/questions/728670/functions-that-are-their-own-fourier-transform https://math.stackexchange.com/questions/728670/functions-th... [1] https://en.wikipedia.org/wiki/Hermite_polynomials#Hermite_functions_as_eigenfunctions_of_the_Fourier_transform https://en.wikipedia.org/wiki/Hermite_polynomials#Hermite_fu...
  • perihelions 1y ago
    As well as the linear combinations (including infinite sums!) of Hermite functions with the same eigenvalue under the Fourier transform. (Those eigenvalues are infinitely degenerate). You could express sech(x) as such a sum.