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It's not intended in that the compiler may have optimized based on the assumption that you have now gone and violated via an unsafe block. Just as in C that wou
by fc417fc802 2y ago
It's not intended in that the compiler may have optimized based on the assumption that you have now gone and violated via an unsafe block. Just as in C that would produce undefined behavior in that there's no telling what consequences the optimization might have. The lack of a formal specification isn't relevant.