2 ms·
> I'm not going into how much this is not E2E, as this has already been proven By whom? It looks like E2E to me. It’s just that both ends are controlled by the
by otterley 2y ago
> I'm not going into how much this is not E2E, as this has already been proven
By whom? It looks like E2E to me. It’s just that both ends are controlled by the same entity.