I can't quite parse your statement, but if you mean that bytemuck doesn't let you "rely on the exact binary layout of something in memory", then yes, it does: i

I can't quite parse your statement, but if you mean that bytemuck doesn't let you "rely on the exact binary layout of something in memory", then yes, it does: it lets you cast from a Pod type to another Pod type, which exposes the memory layout of both types.