3 ms·

Okay, but doesn't Bar nevertheless inherit Foo's methods in the sense of interface inheritance? Or does code that gets passed a Bar not get access to Foo's meth

• the_mitsuhiko 2y ago
  > does code that gets passed a Bar not get access to Foo's methods Prior to the current version of Rust it was impossible to access methods on `Foo` when a `&dyn Bar` was passed. With the current beta version you can upcast.
  • ogoffart 2y ago
    > Prior to the current version of Rust it was impossible to access methods on `Foo` when a `&dyn Bar` was passed. This has been working since Rust 1.0, I think: trait Foo { fn foo(&self); } trait Bar : Foo {} impl Foo for () { fn foo(&self) { println!("Hello") } } impl Bar for () {} fn xxx(x: &dyn Bar) { x.foo(); } pub fn main() { xxx(&()); } > With the current beta version you can upcast Right. Now you can convert from `&dyn Bar` to `&dyn Foo` which wasn't possible before.
    • the_mitsuhiko 2y ago
      Inherent method implementations were unavailable. (Eg: impl dyn Foo) and then call this via Bar.