I think you may have misunderstood the proposal. Your 3rd party library example would have to write `pystd2025::HashMap<pystd2025::U8String, size_t> member;`. I

I think you may have misunderstood the proposal. Your 3rd party library example would have to write `pystd2025::HashMap<pystd2025::U8String, size_t> member;`. Isn't that stable? From the post: The sample code above used the pystd namespace. It does not actually exist. Instead it is defined like this in the cpp file: #include <pystd2025.hpp> namespace pystd = pystd2025;