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If the sight is angled down relative to the barrel, the barrel is angled up relative to the sight. But which is angled "straight"? The shooter aims with the si
by solidsnack9000 2y ago
If the sight is angled down relative to the barrel, the barrel is angled up relative to the sight. But which is angled "straight"?
The shooter aims with the sight, so if the target is level with the shooter's eye, the sights are level and the barrel is pointed (ever so slightly) up.
This means you are basically correct, in that the boreline is always pointed higher than where the bullet actually is (setting aside any lift the bullet generates, but that is a lot of detail to get into). However, the bullet does often move upwards relative to the ground (for some distance) since people are often aiming almost level to the ground. So in that sense, the trajectories are not "all drop". That is why I think you are being downvoted.
- rtkwe 2y agoYeah, should have said all drop relative to the point of aim/sight line I suppose, wrote for an audience more familiar with guns than HN probably is. Things are usually reference relative to the sight because that's what you're aiming with so movement relative to that is how you'd adjust your aim to actually hit the target. There's not really any mechanism for lift though, the bullet is not an airfoil and is traveling directly into the airflow so there's not going to be any lifting body effects either while it's in stable flight and after that it's tumbling so there might be some then but it will be chaotic and inconsistent and you're just as likely to have it pushed down if the tail is up.