2 ms·
There will be some attenuation, but the output is focused into a beam, so you don't get the usual inverse square falloff with distance.
by mrob 2y ago
There will be some attenuation, but the output is focused into a beam, so you don't get the usual inverse square falloff with distance.
- ty6853 2y agoYou do, there is just a greater gain factor constant.