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no lol you're just missing the question I am asking. obviously sizeof wont return a pointer. Im just saying, wouldn't it be `sizeof(usize)` essentially... or `s
by sweeter 2y ago
no lol you're just missing the question I am asking. obviously sizeof wont return a pointer. Im just saying, wouldn't it be `sizeof(usize)` essentially... or `sizeof(ptr_size_on_platform)`