3 ms·
Mass = 10,000kg (per the initial topic) Force = 0.236N (per your link) Acceleration = 0.0000236m/s (acceleration = force / mass) Seconds in 2 months = 525960
by somenameforme 2y ago
Mass = 10,000kg (per the initial topic)
Force = 0.236N (per your link)
Acceleration = 0.0000236m/s (acceleration = force / mass)
Seconds in 2 months = 5259600
Final Velocity after 2 months = 277 miles per hour (0.124km/s)
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This is an extremely naive and optimistic calculation since I'm assuming the engine is weightless and does not require fuel or power. It's easier that way and still emphasizes the point perfectly fine. You're gonna need a lot more engines to get anywhere. And of course a 10 ton ship is not practical. The goal for Starship is to to have a payload in the hundreds of tons, let alone the entire vessel's mass.
You also only have half the distance to accelerate, because you then need to turn around and decelerate the remaining distance. And we're also ignoring landing/takeoff which obviously isn't happening.
- trhway 2y ago>Mass = 10,000kg (per the initial topic) >Force = 0.236N (per your link) >I'm assuming the engine is weightless and does not require fuel or power. 10KW 10kg engine plus 40 kg expelled mass per 100kg total starting mass. Thus for 10000kg - 1000kg of 100 x 10kg 10KW engines, 4 tons expelled mass, 2.5 tons - solar panels providing power. 1 engine - 0.3N, 100 engines - 30N. 15km/s in under 2 months, plus 2 months deceleration. The same for 100ton ship or 1000ton. >landing/takeoff that is by local chemical Starships "shuttles" which would transfer people and cargo to/from the interplanetary ships. Using Starship shuttles to fuel the interplanetary Starship, though chemical one, has long been in the published SpaceX/Musk plans.