2 ms·
On modern 64-bit machines, sizeof(int) != sizeof(int*) is very true. But there's probably a significant amount of code that assumes it's equal to sizeof(uint64_
by tomsmeding 2y ago
On modern 64-bit machines, sizeof(int) != sizeof(int*) is very true. But there's probably a significant amount of code that assumes it's equal to sizeof(uint64_t) or sizeof(long). :)