3 ms·
This is downvoted, but correct. Which door is right and which door is wrong doesn't get reshuffled when the host removes a wrong door, so even though there's o
by Izkata 2y ago
This is downvoted, but correct. Which door is right and which door is wrong doesn't get reshuffled when the host removes a wrong door, so even though there's only 2 doors left the chance isn't 50:50, it's still 33:67 - with the player having most likely chosen a wrong door.
- alexey-salmin 2y agoIt's not correct. P(A|B)=P(A) only if A and B are independent. Requiring independence in this case literally means "the host opens the door regardless of the player making the right or wrong choice first time". It's a core assumption in your calculations, without it the math is not correct.