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> If they were to design that today, I think they would require the initialization expression to be constexpr. Why would they? This (non-constexpr) semantic w
by j16sdiz 2y ago
> If they were to design that today, I think they would require the initialization expression to be constexpr.
Why would they?
This (non-constexpr) semantic would be useful as lazy initialization. .. and C++ love tiny little features like these.