Yes you're right, but the code I posted above still doesn't work. It works fine with PHP 5.4 though. This also fails with the same error message: $fn = funct

Yes you're right, but the code I posted above still doesn't work. It works fine with PHP 5.4 though. This also fails with the same error message: $fn = function() { echo 'foo'; }; But that's also perfectly valid PHP 5.4 code. Maybe I'm doing something wrong, idk.