The proposed behavior is the opposite of how Swift and Rust use ?. `foo?.bar()` invokes `foo.bar()` in the non-error case, while in Go `foo ? { bar() }` invokes

The proposed behavior is the opposite of how Swift and Rust use ?. `foo?.bar()` invokes `foo.bar()` in the non-error case, while in Go `foo ? { bar() }` invokes it in the error case.