4 ms·

and that means?

• kelseyfrog 2y ago
  Depends on your alpha ;) . But it's significant.
  • viraptor 2y ago
    That really does not answer the question.
• jampekka 2y ago
  That there's a probability of 4.20e-05 that the observed difference of that large would happen by chance due to observation noise if there would be no real difference (given your assumptions about the data generating process holds).
  • tstenner 2y ago
    The normality assumption is a large stretch, especially since there an absolute lower limit near the observation and a somewhat discrete distribution, so a t-test isn't appropriate. But then again it looks significant, so there's no real need for a test
    • jampekka 2y ago
      Something like Mann-Whitney U would be safer. But it's indeed quite obvious from the samples that the difference is robust.
• lmm 2y ago
  Evidence more than strong enough to be published in most fields. Not quite strong enough to qualify as "discovery" in high-energy physics.
• pjdesno 2y ago
  In a lot of fields, p=0.05 is good enough to publish. p=0.0001 means it's really f*ing unlikely that the difference in means is due to random chance.