4 ms·
This works, but gives you no indication of whether the tile is partially visible or not, much less how visible. An accurate indication of this would require man
by JasonSage 14y ago
This works, but gives you no indication of whether the tile is partially visible or not, much less how visible. An accurate indication of this would require many more rays and a lot of processing.
- 0x0 14y agoRight. I was thinking about whether there could be a way to apply your technique, without having to do the polar + cartesian conversions.