4 ms·
i couldnt come up with a proof for the initial problem (n^6+n^3+2n^2 is a multiple of 6 for every n) because it's not true (simply insert 1, 2, 4 or 5)
by daef 2y ago
i couldnt come up with a proof for the initial problem (n^6+n^3+2n^2 is a multiple of 6 for every n)
because it's not true (simply insert 1, 2, 4 or 5)
- goldencoralefan 2y agoYou’re missing a term: n^6+n^3+2n^2+2n
- deleted 2y ago[deleted]