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The core of the UNIX time is seconds since epoch, nothing else. 'Day' has no special place at all. There are calendars for converting to and from dates, inclu
by DamonHD 2y ago
The core of the UNIX time is seconds since epoch, nothing else. 'Day' has no special place at all. There are calendars for converting to and from dates, including Western-style, but the days in those calendars vary in length because of daylight saving switches and leap seconds for example.
- Kwpolska 2y agoUNIX time ignores leap seconds, so every day is exactly 86400 seconds, and every year is either 365*86400 or 366*86400 seconds. This makes converting from yyyy-mm-dd to UNIX time quite easy, as you can just do `365*86400*(yyyy-1970) + leap_years*86400` to get to yyyy-01-01.
- XorNot 2y agoWell yes, in the sense that not all Unix epoch seconds are equally long...
- sylware 2y agoYeap, this is why I said it is kind of easy. Until you know properly the leap years. Leap year rules on the long run are are bit funky. Just have a look at wikipedia. (do not use gogol search since they are now forcing javascript by default)
- sylware 2y agoYou are perfectly wrong, the day is the main calendar object related to the epoch seconds. I wrote conversion code, I know what I am talking about.