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Is it definitely the LCD? Given drive of size 15 and 20 the LCD would be 1, no? I had assumed it would just use the size of the smallest drive on every drive (s
by wrboyce 2y ago
Is it definitely the LCD? Given drive of size 15 and 20 the LCD would be 1, no? I had assumed it would just use the size of the smallest drive on every drive (so 15+20->15+15=30). When I first read your comment I was thinking of GCF but even that would be fairly inefficient (GCF(15,20) = 5, so 15+20->5+5=10).