3 ms·
You can't have a variable of type void, but you can have an expression of type void - calling a function that returns void does just that (in C++, "throw" is al
by int_19h 2y ago
You can't have a variable of type void, but you can have an expression of type void - calling a function that returns void does just that (in C++, "throw" is also a void-typed expression).