3 ms·
it's simply "Generic Operator". The only requirements is to follow axioms for all its input values. NAND isn't THE operator, it is AN operator that can be in t
by NooneAtAll3 2y ago
it's simply "Generic Operator". The only requirements is to follow axioms for all its input values.
NAND isn't THE operator, it is AN operator that can be in that place.
If there's only 1 value that variables can be - "I", then "I \dot I = I" would be a valid operator that follows given axioms