3 ms·
Wasn't there a paper from Heidi Howard that stated you it's not actually f failures in 2f+1 nodes, but you can actually make the number of nodes that can fail a
by sargun 2y ago
Wasn't there a paper from Heidi Howard that stated you it's not actually f failures in 2f+1 nodes, but you can actually make the number of nodes that can fail a lot higher, if you have some nodes that have to take part in the quorum (or the prior proposal)? This feels roughly similar?
- foota 2y agoI think that's a different thing... I believe you're talking about flexible paxos (https://arxiv.org/abs/1608.06696 https://arxiv.org/abs/1608.06696). Flexible paxos doesn't change the underlying guarantees at all, whereas this does.