4 ms·
E^2 = (mc^2)^2 + (pc)^2, where p is momentum. When an object is traveling at relativistic speeds, the momentum forms a more significant portion of its energy
by ijustlovemath 2y ago
E^2 = (mc^2)^2 + (pc)^2,
where p is momentum. When an object is traveling at relativistic speeds, the momentum forms a more significant portion of its energy