3 ms·What do you mean by x^x^x^... = 2? Isn't the solution to that sqrt(2)?by rak1507 2y agoWhat do you mean by x^x^x^... = 2? Isn't the solution to that sqrt(2)?77pt77 2y agof(x,n) = f(x,n-1) ^ x f(x,1) = x c_n is such that f(c_n,n) = 2 c = lim c_nrak1507 2y agoDo you mean f(x,n-1)^x or x^f(x,n-1)? With the first definition, c=1, the second, c=sqrt(2). I'm still not seeing the connection to omega.