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No. The reason perturbation theory doesn’t work as well for QCD as it does for QED is because of two reasons: 1. The coupling constant of QCD is much higher th
by frutiger 2y ago
No. The reason perturbation theory doesn’t work as well for QCD as it does for QED is because of two reasons:
1. The coupling constant of QCD is much higher than QED so contributions to the overall result from Feynman diagrams that have more vertices (the multiplicative factor of each element in the sum is proportional to the power of the number of vertices) don’t vanish as quickly as they do for QED
2. The gauge bosons in QCD (i.e. gluons) themselves have colour charge whereas those in QED (i.e. photons) do not have electrical charge.
- whatshisface 2y agoYou can't give a definite no to that because, since gravitons have stress-energy and are non-perturbative, a field theory advance that worked for them could also help with the strong force.
- frutiger 2y agoI mean sure, since we don't know what GR + QFT could look like, the result could be just about anything and somehow give us nice closed solutions to QCD problems. But I don't feel like that line of reasoning is particularly useful.
- whatshisface 2y agoAdS/CFT is already an example of an approach to gravity yielding an approach to strongly coupled field theories.
- l33tman 2y agoIt's an approach to a hypothetical other type of universe's gravity..