2 ms·
Very simple. Either: $copy = $original; Or, if you must have a function, function array_copy(array $a) { return $a; } Arrays use the no
by ircmaxell 14y ago
Very simple.
Either:
$copy = $original;
Or, if you must have a function,
function array_copy(array $a) {
return $a;
}
Arrays use the normal copy-on-write semantics of PHP. They are not passed by reference or object handle...
The only potential issue is if the array contains references deeper in.