3 ms·

And then have a union between the two different kinds of pointers, and a tag to tell which one is in use, then test that tag everywhere? Why? What good does it

And then have a union between the two different kinds of pointers, and a tag to tell which one is in use, then test that tag everywhere? Why? What good does it bring for that extra complexity?

zabzonk 2y ago
Doesn't the name of the function select for the types and use of the parameters? But I haven't written in C for a long time, and this I think could be done more clearly in C++.
- Sesse__ 2y ago
  You're saying you would write the entire hash table four times, with everything duplicated and no reuse? Again: Why? What do you gain compared to one line to suppress a warning?
  - zabzonk 2y ago
    Clarity? And in C++ at least, I would re-write the functions.