> std::move is just std::copy with a compiler-defined constructor invocation potentially run to determine the old value I have no idea what that means. std::m

> std::move is just std::copy with a compiler-defined constructor invocation potentially run to determine the old value I have no idea what that means. std::move is a cast to an rvalue reference. That can potentially trigger a specific overloaded function to be selected and possibly, ultimately, a move constructor or assignment operator to be called. For an explicit move to be profitable, an expression would have otherwise chosen a copy constructor for a type with an expensive copy constructor and a cheap move constructor. std::copy is a range algorithm, not sure what's the relevance.