Not that anybody asked me, but I think about it like this: You have a field (a set of "numbers"). Multiplication is defined over the field. You want to invent

Not that anybody asked me, but I think about it like this: You have a field (a set of "numbers"). Multiplication is defined over the field. You want to invent a notion of division. Let's introduce the notation "a/b" to refer to some member of a field such that "a/b" * b = a. As Hillel points out, you can identify "a/b" with a*inverse(b), where "inverse" is the multiplicative inverse. And yes, there is no inverse(0). But really let's just stick with the previous definition: "a/b" * b = a. Now consider "a/0". If "a/0" is in the field, then "a/0" * 0 = a. Let's consider the case where a != 0. Then we have "a/0" * 0 != 0. But this cannot be true if "a/0" is in the field, because for every x we have x * 0 = 0. Thus "a/0" is not in the field. Consider "a/0" with a=0. Then "a/0" * 0 = 0. Any member of the field satisfies this equation, because for every x we have x * 0 = 0. So, "a/0" could be any member of the field. Our definition of division does not determine "0/0". Whether you can assign "1/0" to a member of the field (such as 0) depends on how you define division.