5 ms·

I’m confused by what I see. It looks like nothing actually disappears. I expected a black hole to not just affect what an area looked like, but also to “disapp

I’m confused by what I see. It looks like nothing actually disappears. I expected a black hole to not just affect what an area looked like, but also to “disappear” some part of what was there.

useless_foghorn 2y ago
I think that’s why this demonstration is interesting. It’s showing how the light can be bent around the black hole. Anything that crosses the event horizon won’t be coming back, but because of the lensing of the light you can “see” behind a black hole.
- jtbayly 2y ago
  So if I’m understanding correctly, the black hole is supposed to be between me and what I’m looking at, not in what I’m looking at? If so, then my question is wouldn’t some light be lost to the black hole? Shouldn’t a substantial portion of the light coming at me from the other side of the black hole disappear into the black hole, making what does lens around dimmer?
  - bmurphy1976 2y ago
    Yes some light would be lost the black hole, but also some light you would not have normally seen is now coming your way due to space time warping.
    - hunter2_ 2y ago
      When you say "normally," do you mean all else being equal except no black hole? Or substitute an opaque mass for the black hole?
  - ayakang31415 2y ago
    Here's Veritasium video on Gravitational Lensing effect: https://www.youtube.com/watch?v=zUyH3XhpLTo https://www.youtube.com/watch?v=zUyH3XhpLTo
  - useless_foghorn 2y ago
    A lot of light would be absorbed by the black hole. A lot of light paths would be bent and miss or nearly miss the black hole, making edges of the black hole quite bright. The dimming effect would be much larger than the (brighter) immediate periphery.
cft 2y ago
Because, for an external observer, time infinitely slows down near the event horizon. In other words, during one hour by the clock of the far-away observer, the time that passes by the clock of the falling observer approaches zero as he approaches the event horizon. So, when you look from the outside, objects get 'frozen' as they approach the event horizon. For the falling observer, nothing special happens at the event horizon, and he just falls through. If you happen to approach the event horizon closely and come back again far away to where you started, you will see that a lot of time passed at your origin, while by your clock, the trip might have been short.

I’m confused by what I see. It looks like nothing actually disappears. I expected a black hole to not just affect what an area looked like, but also to “disappear” some part of what was there.

useless_foghorn 2y ago

I think that’s why this demonstration is interesting. It’s showing how the light can be bent around the black hole. Anything that crosses the event horizon won’t be coming back, but because of the lensing of the light you can “see” behind a black hole.

jtbayly 2y ago
So if I’m understanding correctly, the black hole is supposed to be between me and what I’m looking at, not in what I’m looking at? If so, then my question is wouldn’t some light be lost to the black hole? Shouldn’t a substantial portion of the light coming at me from the other side of the black hole disappear into the black hole, making what does lens around dimmer?
- bmurphy1976 2y ago
  Yes some light would be lost the black hole, but also some light you would not have normally seen is now coming your way due to space time warping.
  - hunter2_ 2y ago
    When you say "normally," do you mean all else being equal except no black hole? Or substitute an opaque mass for the black hole?
- ayakang31415 2y ago
  Here's Veritasium video on Gravitational Lensing effect: https://www.youtube.com/watch?v=zUyH3XhpLTo https://www.youtube.com/watch?v=zUyH3XhpLTo
- useless_foghorn 2y ago
  A lot of light would be absorbed by the black hole. A lot of light paths would be bent and miss or nearly miss the black hole, making edges of the black hole quite bright. The dimming effect would be much larger than the (brighter) immediate periphery.

cft 2y ago

Because, for an external observer, time infinitely slows down near the event horizon. In other words, during one hour by the clock of the far-away observer, the time that passes by the clock of the falling observer approaches zero as he approaches the event horizon. So, when you look from the outside, objects get 'frozen' as they approach the event horizon. For the falling observer, nothing special happens at the event horizon, and he just falls through. If you happen to approach the event horizon closely and come back again far away to where you started, you will see that a lot of time passed at your origin, while by your clock, the trip might have been short.