4 ms·
> This is not true in C, where you can reference the shared memory after the lock is released. technically yes but practically this is nearly always programmer
by dathinab 2y ago
> This is not true in C, where you can reference the shared memory after the lock is released.
technically yes but practically this is nearly always programmer bug to bypass a lock
- freeone3000 2y agoThat is the point — this is (another) example of a programmer bug that C allows that Rust does not.