3 ms·
It's not actually about `*` -- for instance, declaring `const T = *T;` emits an error. The thing that makes this okay is that field types (for structs and union
by mlugg 2y ago
It's not actually about `*` -- for instance, declaring `const T = *T;` emits an error. The thing that makes this okay is that field types (for structs and unions) are evaluated in the "lazy" way you describe.
- xg15 2y agoAh, that makes sense. Thank you!